Final answer to the problem
$y=\sqrt{1-x^2},\:y=-\sqrt{1-x^2}$
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Step-by-step Solution
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1
Apply the formula: $x+a=b$$\to x=b-a$, where $a=x^2$, $b=1$, $x+a=b=x^2+y^2=1$, $x=y^2$ and $x+a=x^2+y^2$
$y^2=1-x^2$
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$y^2=1-x^2$
Learn how to solve problems step by step online. Solve the equation x^2+y^2=1. Apply the formula: x+a=b\to x=b-a, where a=x^2, b=1, x+a=b=x^2+y^2=1, x=y^2 and x+a=x^2+y^2. Apply the formula: x^a=b\to \left(x^a\right)^{\frac{1}{a}}=\pm b^{\frac{1}{a}}, where a=2, b=1-x^2 and x=y. Apply the formula: \left(x^a\right)^b=x, where a=2, b=1, x^a^b=\sqrt{y^2}, x=y and x^a=y^2. Apply the formula: a=\pm b\to a=b,\:a=-b, where a=y and b=\sqrt{1-x^2}.
Final answer to the problem
$y=\sqrt{1-x^2},\:y=-\sqrt{1-x^2}$
