Solve the quadratic equation $x^2-2x+1=0$

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Final answer to the problem

$x=1,\:x=1$
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Apply the formula: $x^2+bx+c=0$$\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}$, where $b=-2$, $c=1$, $bx=-2x$, $x^2+bx=x^2-2x+1$ and $x^2+bx=0=x^2-2x+1=0$

$x=\frac{2\pm \sqrt{{\left(-2\right)}^2-4\cdot 1}}{2}$

Learn how to solve equazioni quadratiche problems step by step online.

$x=\frac{2\pm \sqrt{{\left(-2\right)}^2-4\cdot 1}}{2}$

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Learn how to solve equazioni quadratiche problems step by step online. Solve the quadratic equation x^2-2x+1=0. Apply the formula: x^2+bx+c=0\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}, where b=-2, c=1, bx=-2x, x^2+bx=x^2-2x+1 and x^2+bx=0=x^2-2x+1=0. Apply the formula: a=b\to a=b, where a=x and b=\frac{2\pm \sqrt{{\left(-2\right)}^2-4\cdot 1}}{2}. Apply the formula: x=\frac{b\pm c}{f}\to x=\frac{b+c}{f},\:x=\frac{b-c}{f}, where b=2, c=0 and f=2. Apply the formula: a+b=a+b, where a=2, b=0 and a+b=2+0.

Final answer to the problem

$x=1,\:x=1$

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Function Plot

Plotting: $x^2-2x+1$

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1
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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Equazioni quadratiche

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