Here, we show you a step-by-step solved example of matrices. This solution was automatically generated by our smart calculator:
Rewrite the fraction $\frac{1}{\left(x-1\right)^2\left(x+4\right)^2}$ in $4$ simpler fractions using partial fraction decomposition
Find the values for the unknown coefficients: $A, B, C, D$. The first step is to multiply both sides of the equation from the previous step by $\left(x-1\right)^2\left(x+4\right)^2$
Multiplying polynomials
Simplifying
Assigning values to $x$ we obtain the following system of equations
Proceed to solve the system of linear equations
Rewrite as a coefficient matrix
Reducing the original matrix to a identity matrix using Gaussian Elimination
The integral of $\frac{1}{\left(x-1\right)^2\left(x+4\right)^2}$ in decomposed fractions equals
Rewrite the fraction $\frac{1}{\left(x-1\right)^2\left(x+4\right)^2}$ in $4$ simpler fractions using partial fraction decomposition
Expand the integral $\int\left(\frac{1}{25\left(x-1\right)^2}+\frac{1}{25\left(x+4\right)^2}+\frac{-2}{125\left(x-1\right)}+\frac{2}{125\left(x+4\right)}\right)dx$ into $4$ integrals using the sum rule for integrals, to then solve each integral separately
Take the constant $\frac{1}{25}$ out of the integral
Apply the formula: $\int\frac{n}{\left(x+a\right)^c}dx$$=\frac{-n}{\left(c-1\right)\left(x+a\right)^{\left(c-1\right)}}+C$, where $a=-1$, $c=2$ and $n=1$
Simplify the expression
The integral $\int\frac{1}{25\left(x-1\right)^2}dx$ results in: $\frac{-1}{25\left(x-1\right)}$
Take the constant $\frac{1}{25}$ out of the integral
Apply the formula: $\int\frac{n}{\left(x+a\right)^c}dx$$=\frac{-n}{\left(c-1\right)\left(x+a\right)^{\left(c-1\right)}}+C$, where $a=4$, $c=2$ and $n=1$
Simplify the expression
The integral $\int\frac{1}{25\left(x+4\right)^2}dx$ results in: $\frac{-1}{25\left(x+4\right)}$
Take the constant $\frac{1}{125}$ out of the integral
Apply the formula: $\int\frac{n}{x+b}dx$$=nsign\left(x\right)\ln\left(x+b\right)+C$, where $b=-1$ and $n=-2$
Multiply the fraction and term in $-2\left(\frac{1}{125}\right)\ln\left|x-1\right|$
The integral $\int\frac{-2}{125\left(x-1\right)}dx$ results in: $-\frac{2}{125}\ln\left(x-1\right)$
Take the constant $\frac{1}{125}$ out of the integral
Apply the formula: $\int\frac{n}{x+b}dx$$=nsign\left(x\right)\ln\left(x+b\right)+C$, where $b=4$ and $n=2$
Multiply the fraction and term in $2\left(\frac{1}{125}\right)\ln\left|x+4\right|$
The integral $\int\frac{2}{125\left(x+4\right)}dx$ results in: $\frac{2}{125}\ln\left(x+4\right)$
Gather the results of all integrals
As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$
Accedete a soluzioni dettagliate passo dopo passo per migliaia di problemi, che crescono ogni giorno!
I problemi più comuni risolti con questa calcolatrice: