$\lim_{x\to0}\left(x^2+x+\frac{1}{4}\right)$

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Final answer to the problem

$\frac{1}{4}$
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The limit of a sum of two or more functions is equal to the sum of the limits of each function: $\displaystyle\lim_{x\to c}(f(x)\pm g(x))=\lim_{x\to c}(f(x))\pm\lim_{x\to c}(g(x))$

$\lim_{x\to0}\left(x^2\right)+\lim_{x\to0}\left(x\right)+\lim_{x\to0}\left(\frac{1}{4}\right)$

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$\lim_{x\to0}\left(x^2\right)+\lim_{x\to0}\left(x\right)+\lim_{x\to0}\left(\frac{1}{4}\right)$

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Learn how to solve limiti per sostituzione diretta problems step by step online. (x)->(0)lim(x^2+x1/4). The limit of a sum of two or more functions is equal to the sum of the limits of each function: \displaystyle\lim_{x\to c}(f(x)\pm g(x))=\lim_{x\to c}(f(x))\pm\lim_{x\to c}(g(x)). Apply the formula: \lim_{x\to c}\left(a\right)=a, where a=\frac{1}{4} and c=0. Evaluate the limit \lim_{x\to0}\left(x^2\right) by replacing all occurrences of x by 0. Apply the formula: x+0=x.

Final answer to the problem

$\frac{1}{4}$

Exact Numeric Answer

$0.25$

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Plotting: $x^2+x+\frac{1}{4}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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