Esercizio
$\frac{\left(x^3-5x^2-5x-3\right)}{x+11}$
Soluzione passo-passo
1
Dividere $x^3-5x^2-5x-3$ per $x+11$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+11;}{\phantom{;}x^{2}-16x\phantom{;}+171\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+11\overline{\smash{)}\phantom{;}x^{3}-5x^{2}-5x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+11;}\underline{-x^{3}-11x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{3}-11x^{2};}-16x^{2}-5x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+11-;x^n;}\underline{\phantom{;}16x^{2}+176x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}16x^{2}+176x\phantom{;}-;x^n;}\phantom{;}171x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+11-;x^n-;x^n;}\underline{-171x\phantom{;}-1881\phantom{;}\phantom{;}}\\\phantom{;;-171x\phantom{;}-1881\phantom{;}\phantom{;}-;x^n-;x^n;}-1884\phantom{;}\phantom{;}\\\end{array}$
$x^{2}-16x+171+\frac{-1884}{x+11}$
Risposta finale al problema
$x^{2}-16x+171+\frac{-1884}{x+11}$