$\frac{x^2-20+x}{x+5}$

Step-by-step Solution

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Final answer to the problem

$x-4$
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Step-by-step Solution

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1

Factor the trinomial $x^2-20+x$ finding two numbers that multiply to form $-20$ and added form $1$

$\begin{matrix}\left(-4\right)\left(5\right)=-20\\ \left(-4\right)+\left(5\right)=1\end{matrix}$

Learn how to solve divisione lunga polinomiale problems step by step online.

$\begin{matrix}\left(-4\right)\left(5\right)=-20\\ \left(-4\right)+\left(5\right)=1\end{matrix}$

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Learn how to solve divisione lunga polinomiale problems step by step online. (x^2-20x)/(x+5). Factor the trinomial x^2-20+x finding two numbers that multiply to form -20 and added form 1. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Simplifying.

Final answer to the problem

$x-4$

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Function Plot

Plotting: $x-4$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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