Esercizio
$\frac{\left(x^4+x^3-11x^2+11x-3\right)}{x-3}$
Soluzione passo-passo
1
Dividere $x^4+x^3-11x^2+11x-3$ per $x-3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-3;}{\phantom{;}x^{3}+4x^{2}+x\phantom{;}+14\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-3\overline{\smash{)}\phantom{;}x^{4}+x^{3}-11x^{2}+11x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-3;}\underline{-x^{4}+3x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}+3x^{3};}\phantom{;}4x^{3}-11x^{2}+11x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-3-;x^n;}\underline{-4x^{3}+12x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-4x^{3}+12x^{2}-;x^n;}\phantom{;}x^{2}+11x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-3-;x^n-;x^n;}\underline{-x^{2}+3x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-x^{2}+3x\phantom{;}-;x^n-;x^n;}\phantom{;}14x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-3-;x^n-;x^n-;x^n;}\underline{-14x\phantom{;}+42\phantom{;}\phantom{;}}\\\phantom{;;;-14x\phantom{;}+42\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}39\phantom{;}\phantom{;}\\\end{array}$
$x^{3}+4x^{2}+x+14+\frac{39}{x-3}$
Risposta finale al problema
$x^{3}+4x^{2}+x+14+\frac{39}{x-3}$