Simplify $\left(j^{-3}\right)^5$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $-3$ and $n$ equals $5$

Applicare la formula: $ab$$=ab$, dove $ab=-3\cdot 5$, $a=-3$ e $b=5$

Applicare la formula: $\frac{a^m}{a^n}$$=a^{\left(m-n\right)}$, dove $a^n=j^{-15}$, $a^m=j^{-8}$, $a=j$, $a^m/a^n=\frac{-6j^{-8}}{-2j^{-15}}$, $m=-8$ e $n=-15$

Applicare la formula: $\frac{ab}{c}$$=\frac{a}{c}b$, dove $ab=-6j^{7}$, $a=-6$, $b=j^{7}$, $c=-2$ e $ab/c=\frac{-6j^{7}}{-2}$