Esercizio
$\frac{10x^4\:-6x^3+2x^2-3x+8}{x-1}$
Soluzione passo-passo
1
Dividere $10x^4-6x^3+2x^2-3x+8$ per $x-1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-1;}{\phantom{;}10x^{3}+4x^{2}+6x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-1\overline{\smash{)}\phantom{;}10x^{4}-6x^{3}+2x^{2}-3x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-1;}\underline{-10x^{4}+10x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-10x^{4}+10x^{3};}\phantom{;}4x^{3}+2x^{2}-3x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n;}\underline{-4x^{3}+4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-4x^{3}+4x^{2}-;x^n;}\phantom{;}6x^{2}-3x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n;}\underline{-6x^{2}+6x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-6x^{2}+6x\phantom{;}-;x^n-;x^n;}\phantom{;}3x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n-;x^n;}\underline{-3x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;;;-3x\phantom{;}+3\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}11\phantom{;}\phantom{;}\\\end{array}$
$10x^{3}+4x^{2}+6x+3+\frac{11}{x-1}$
Risposta finale al problema
$10x^{3}+4x^{2}+6x+3+\frac{11}{x-1}$