Esercizio
$\frac{2x^2+x-8}{x+2}$
Soluzione passo-passo
1
Dividere $2x^2+x-8$ per $x+2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+2;}{\phantom{;}2x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+2\overline{\smash{)}\phantom{;}2x^{2}+x\phantom{;}-8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+2;}\underline{-2x^{2}-4x\phantom{;}\phantom{-;x^n}}\\\phantom{-2x^{2}-4x\phantom{;};}-3x\phantom{;}-8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+2-;x^n;}\underline{\phantom{;}3x\phantom{;}+6\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}3x\phantom{;}+6\phantom{;}\phantom{;}-;x^n;}-2\phantom{;}\phantom{;}\\\end{array}$
$2x-3+\frac{-2}{x+2}$
Risposta finale al problema
$2x-3+\frac{-2}{x+2}$