Esercizio
$\frac{2x^2-2x+3}{x+1}$
Soluzione passo-passo
1
Dividere $2x^2-2x+3$ per $x+1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+1;}{\phantom{;}2x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+1\overline{\smash{)}\phantom{;}2x^{2}-2x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+1;}\underline{-2x^{2}-2x\phantom{;}\phantom{-;x^n}}\\\phantom{-2x^{2}-2x\phantom{;};}-4x\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n;}\underline{\phantom{;}4x\phantom{;}+4\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}4x\phantom{;}+4\phantom{;}\phantom{;}-;x^n;}\phantom{;}7\phantom{;}\phantom{;}\\\end{array}$
Risposta finale al problema
$2x-4+\frac{7}{x+1}$