Esercizio
$\frac{2x^3+x^2-x+3}{2x+3}$
Soluzione passo-passo
1
Dividere $2x^3+x^2-x+3$ per $2x+3$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+3;}{\phantom{;}x^{2}-x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+3\overline{\smash{)}\phantom{;}2x^{3}+x^{2}-x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+3;}\underline{-2x^{3}-3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{3}-3x^{2};}-2x^{2}-x\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n;}\underline{\phantom{;}2x^{2}+3x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}2x^{2}+3x\phantom{;}-;x^n;}\phantom{;}2x\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n-;x^n;}\underline{-2x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;;-2x\phantom{;}-3\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$x^{2}-x+1$