Esercizio
$\frac{2x^3-3x^2+4x+8}{2x^2-7x+1}$
Soluzione passo-passo
1
Dividere $2x^3-3x^2+4x+8$ per $2x^2-7x+1$
$\begin{array}{l}\phantom{\phantom{;}2x^{2}-7x\phantom{;}+1;}{\phantom{;}x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{;}2x^{2}-7x\phantom{;}+1\overline{\smash{)}\phantom{;}2x^{3}-3x^{2}+4x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x^{2}-7x\phantom{;}+1;}\underline{-2x^{3}+7x^{2}-x\phantom{;}\phantom{-;x^n}}\\\phantom{-2x^{3}+7x^{2}-x\phantom{;};}\phantom{;}4x^{2}+3x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x^{2}-7x\phantom{;}+1-;x^n;}\underline{-4x^{2}+14x\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{;-4x^{2}+14x\phantom{;}-2\phantom{;}\phantom{;}-;x^n;}\phantom{;}17x\phantom{;}+6\phantom{;}\phantom{;}\\\end{array}$
$x+2+\frac{17x+6}{2x^2-7x+1}$
Risposta finale al problema
$x+2+\frac{17x+6}{2x^2-7x+1}$