Esercizio
$\frac{2x^3-4x^2-5x-3}{x+1}$
Soluzione passo-passo
1
Dividere $2x^3-4x^2-5x-3$ per $x+1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+1;}{\phantom{;}2x^{2}-6x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+1\overline{\smash{)}\phantom{;}2x^{3}-4x^{2}-5x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+1;}\underline{-2x^{3}-2x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{3}-2x^{2};}-6x^{2}-5x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n;}\underline{\phantom{;}6x^{2}+6x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}6x^{2}+6x\phantom{;}-;x^n;}\phantom{;}x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n;}\underline{-x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{;;-x\phantom{;}-1\phantom{;}\phantom{;}-;x^n-;x^n;}-4\phantom{;}\phantom{;}\\\end{array}$
$2x^{2}-6x+1+\frac{-4}{x+1}$
Risposta finale al problema
$2x^{2}-6x+1+\frac{-4}{x+1}$