Esercizio
$\frac{3x^{3}+x-11}{x-1}$
Soluzione passo-passo
1
Dividere $3x^3+x-11$ per $x-1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-1;}{\phantom{;}3x^{2}+3x\phantom{;}+4\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-1\overline{\smash{)}\phantom{;}3x^{3}\phantom{-;x^n}+x\phantom{;}-11\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-1;}\underline{-3x^{3}+3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3x^{3}+3x^{2};}\phantom{;}3x^{2}+x\phantom{;}-11\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n;}\underline{-3x^{2}+3x\phantom{;}\phantom{-;x^n}}\\\phantom{;-3x^{2}+3x\phantom{;}-;x^n;}\phantom{;}4x\phantom{;}-11\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n;}\underline{-4x\phantom{;}+4\phantom{;}\phantom{;}}\\\phantom{;;-4x\phantom{;}+4\phantom{;}\phantom{;}-;x^n-;x^n;}-7\phantom{;}\phantom{;}\\\end{array}$
$3x^{2}+3x+4+\frac{-7}{x-1}$
Risposta finale al problema
$3x^{2}+3x+4+\frac{-7}{x-1}$