Esercizio
$\frac{3x^3-3x^2+3x-1}{x+1}$
Soluzione passo-passo
1
Dividere $3x^3-3x^2+3x-1$ per $x+1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+1;}{\phantom{;}3x^{2}-6x\phantom{;}+9\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+1\overline{\smash{)}\phantom{;}3x^{3}-3x^{2}+3x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+1;}\underline{-3x^{3}-3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3x^{3}-3x^{2};}-6x^{2}+3x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n;}\underline{\phantom{;}6x^{2}+6x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}6x^{2}+6x\phantom{;}-;x^n;}\phantom{;}9x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n;}\underline{-9x\phantom{;}-9\phantom{;}\phantom{;}}\\\phantom{;;-9x\phantom{;}-9\phantom{;}\phantom{;}-;x^n-;x^n;}-10\phantom{;}\phantom{;}\\\end{array}$
$3x^{2}-6x+9+\frac{-10}{x+1}$
Risposta finale al problema
$3x^{2}-6x+9+\frac{-10}{x+1}$