Esercizio
$\frac{5x^3-4x^2-3x-1}{x+1}$
Soluzione passo-passo
1
Dividere $5x^3-4x^2-3x-1$ per $x+1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+1;}{\phantom{;}5x^{2}-9x\phantom{;}+6\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+1\overline{\smash{)}\phantom{;}5x^{3}-4x^{2}-3x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+1;}\underline{-5x^{3}-5x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-5x^{3}-5x^{2};}-9x^{2}-3x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n;}\underline{\phantom{;}9x^{2}+9x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}9x^{2}+9x\phantom{;}-;x^n;}\phantom{;}6x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n;}\underline{-6x\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{;;-6x\phantom{;}-6\phantom{;}\phantom{;}-;x^n-;x^n;}-7\phantom{;}\phantom{;}\\\end{array}$
$5x^{2}-9x+6+\frac{-7}{x+1}$
Risposta finale al problema
$5x^{2}-9x+6+\frac{-7}{x+1}$