Esercizio
$\frac{5x^4-10x^3+16x^2+13x-12}{-5x^2+4}$
Soluzione passo-passo
1
Dividere $5x^4-10x^3+16x^2+13x-12$ per $-5x^2+4$
$\begin{array}{l}\phantom{-5x^{2}+4;}{-x^{2}+2x\phantom{;}-4\phantom{;}\phantom{;}}\\-5x^{2}+4\overline{\smash{)}\phantom{;}5x^{4}-10x^{3}+16x^{2}+13x\phantom{;}-12\phantom{;}\phantom{;}}\\\phantom{-5x^{2}+4;}\underline{-5x^{4}\phantom{-;x^n}+4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-5x^{4}+4x^{2};}-10x^{3}+20x^{2}+13x\phantom{;}-12\phantom{;}\phantom{;}\\\phantom{-5x^{2}+4-;x^n;}\underline{\phantom{;}10x^{3}\phantom{-;x^n}-8x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}10x^{3}-8x\phantom{;}-;x^n;}\phantom{;}20x^{2}+5x\phantom{;}-12\phantom{;}\phantom{;}\\\phantom{-5x^{2}+4-;x^n-;x^n;}\underline{-20x^{2}\phantom{-;x^n}+16\phantom{;}\phantom{;}}\\\phantom{;;-20x^{2}+16\phantom{;}\phantom{;}-;x^n-;x^n;}\phantom{;}5x\phantom{;}+4\phantom{;}\phantom{;}\\\end{array}$
$-x^{2}+2x-4+\frac{5x+4}{-5x^2+4}$
Risposta finale al problema
$-x^{2}+2x-4+\frac{5x+4}{-5x^2+4}$