Esercizio
$\frac{6x^3-11x^2+10x-13}{3x-4}$
Soluzione passo-passo
1
Dividere $6x^3-11x^2+10x-13$ per $3x-4$
$\begin{array}{l}\phantom{\phantom{;}3x\phantom{;}-4;}{\phantom{;}2x^{2}-x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{;}3x\phantom{;}-4\overline{\smash{)}\phantom{;}6x^{3}-11x^{2}+10x\phantom{;}-13\phantom{;}\phantom{;}}\\\phantom{\phantom{;}3x\phantom{;}-4;}\underline{-6x^{3}+8x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-6x^{3}+8x^{2};}-3x^{2}+10x\phantom{;}-13\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x\phantom{;}-4-;x^n;}\underline{\phantom{;}3x^{2}-4x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{2}-4x\phantom{;}-;x^n;}\phantom{;}6x\phantom{;}-13\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x\phantom{;}-4-;x^n-;x^n;}\underline{-6x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{;;-6x\phantom{;}+8\phantom{;}\phantom{;}-;x^n-;x^n;}-5\phantom{;}\phantom{;}\\\end{array}$
$2x^{2}-x+2+\frac{-5}{3x-4}$
Risposta finale al problema
$2x^{2}-x+2+\frac{-5}{3x-4}$