Esercizio
$\frac{8x^5+4x^3+3x^2+9x+16}{2x^3+x^2+3}$
Soluzione passo-passo
1
Dividere $8x^5+4x^3+3x^2+9x+16$ per $2x^3+x^2+3$
$\begin{array}{l}\phantom{\phantom{;}2x^{3}+x^{2}+3;}{\phantom{;}4x^{2}-2x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;}2x^{3}+x^{2}+3\overline{\smash{)}\phantom{;}8x^{5}\phantom{-;x^n}+4x^{3}+3x^{2}+9x\phantom{;}+16\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x^{3}+x^{2}+3;}\underline{-8x^{5}-4x^{4}\phantom{-;x^n}-12x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-8x^{5}-4x^{4}-12x^{2};}-4x^{4}+4x^{3}-9x^{2}+9x\phantom{;}+16\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x^{3}+x^{2}+3-;x^n;}\underline{\phantom{;}4x^{4}+2x^{3}\phantom{-;x^n}+6x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}4x^{4}+2x^{3}+6x\phantom{;}-;x^n;}\phantom{;}6x^{3}-9x^{2}+15x\phantom{;}+16\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x^{3}+x^{2}+3-;x^n-;x^n;}\underline{-6x^{3}-3x^{2}\phantom{-;x^n}-9\phantom{;}\phantom{;}}\\\phantom{;;-6x^{3}-3x^{2}-9\phantom{;}\phantom{;}-;x^n-;x^n;}-12x^{2}+15x\phantom{;}+7\phantom{;}\phantom{;}\\\end{array}$
$4x^{2}-2x+3+\frac{-12x^{2}+15x+7}{2x^3+x^2+3}$
Risposta finale al problema
$4x^{2}-2x+3+\frac{-12x^{2}+15x+7}{2x^3+x^2+3}$