Esercizio
$\frac{9x^3+3x^2+x-1\:}{3x\:-1\:}$
Soluzione passo-passo
1
Dividere $9x^3+3x^2+x-1$ per $3x-1$
$\begin{array}{l}\phantom{\phantom{;}3x\phantom{;}-1;}{\phantom{;}3x^{2}+2x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}3x\phantom{;}-1\overline{\smash{)}\phantom{;}9x^{3}+3x^{2}+x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}3x\phantom{;}-1;}\underline{-9x^{3}+3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-9x^{3}+3x^{2};}\phantom{;}6x^{2}+x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x\phantom{;}-1-;x^n;}\underline{-6x^{2}+2x\phantom{;}\phantom{-;x^n}}\\\phantom{;-6x^{2}+2x\phantom{;}-;x^n;}\phantom{;}3x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x\phantom{;}-1-;x^n-;x^n;}\underline{-3x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;;-3x\phantom{;}+1\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Risposta finale al problema
$3x^{2}+2x+1$