Esercizio
$\frac{d^2}{dx^2}\left(x^3-3xy+y^3-1=0\right)$
Soluzione passo-passo
Passi intermedi
1
Trovare la derivata ($1$)
$3x^{2}-3y-3x\frac{d}{dx}\left(y\right)+3y^{2}\frac{d}{dx}\left(y\right)=0$
Passi intermedi
2
Trovare la derivata ($2$)
$6x+\frac{d}{dx}\left(-3y\right)-3\frac{d}{dx}\left(y\right)-3x\frac{d^2}{dx^2}\left(y\right)+3\frac{d^2}{dx^2}\left(y\right)y^{2}+6\left(\frac{d}{dx}\left(y\right)\right)^2y=0$
Risposta finale al problema
$6x+\frac{d}{dx}\left(-3y\right)-3\frac{d}{dx}\left(y\right)-3x\frac{d^2}{dx^2}\left(y\right)+3\frac{d^2}{dx^2}\left(y\right)y^{2}+6\left(\frac{d}{dx}\left(y\right)\right)^2y=0$