Esercizio
$\frac{d}{dx}\left(3x^2\:cos\left(2x\right)\:\cdot\:\:ln\:\left(3x^2\right)\right)$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. d/dx(3x^2cos(2x)ln(3x^2)). Applicare la formula: \frac{d}{dx}\left(cx\right)=c\frac{d}{dx}\left(x\right). Applicare la formula: \frac{d}{dx}\left(ab\right)=\frac{d}{dx}\left(a\right)b+a\frac{d}{dx}\left(b\right), dove d/dx=\frac{d}{dx}, ab=x^2\cos\left(2x\right)\ln\left(3x^2\right), a=x^2, b=\cos\left(2x\right)\ln\left(3x^2\right) e d/dx?ab=\frac{d}{dx}\left(x^2\cos\left(2x\right)\ln\left(3x^2\right)\right). Applicare la formula: \frac{d}{dx}\left(ab\right)=\frac{d}{dx}\left(a\right)b+a\frac{d}{dx}\left(b\right), dove d/dx=\frac{d}{dx}, ab=\cos\left(2x\right)\ln\left(3x^2\right), a=\cos\left(2x\right), b=\ln\left(3x^2\right) e d/dx?ab=\frac{d}{dx}\left(\cos\left(2x\right)\ln\left(3x^2\right)\right). Applicare la formula: \frac{d}{dx}\left(x^a\right)=ax^{\left(a-1\right)}.
d/dx(3x^2cos(2x)ln(3x^2))
Risposta finale al problema
$6x\cos\left(2x\right)\ln\left(3x^2\right)-6x^2\sin\left(2x\right)\ln\left(3x^2\right)+6x\cos\left(2x\right)$