Applicare la formula: $a\frac{b}{c}$$=\frac{ba}{c}$, dove $a=\csc\left(x\right)$, $b=1$ e $c=\cos\left(x\right)^2$

Riscrivere $\sec\left(x\right)^2+\csc\left(x\right)$ in termini di funzioni seno e coseno.

Applicare la formula: $\frac{\frac{a}{b}}{\frac{c}{f}}$$=\frac{af}{bc}$, dove $a=\csc\left(x\right)$, $b=\cos\left(x\right)^2$, $a/b/c/f=\frac{\frac{\csc\left(x\right)}{\cos\left(x\right)^2}}{\frac{\sin\left(x\right)+\cos\left(x\right)^2}{\cos\left(x\right)^2\sin\left(x\right)}}$, $c=\sin\left(x\right)+\cos\left(x\right)^2$, $a/b=\frac{\csc\left(x\right)}{\cos\left(x\right)^2}$, $f=\cos\left(x\right)^2\sin\left(x\right)$ e $c/f=\frac{\sin\left(x\right)+\cos\left(x\right)^2}{\cos\left(x\right)^2\sin\left(x\right)}$

Applying the trigonometric identity: $\sin\left(\theta \right)\csc\left(\theta \right) = 1$