Esercizio
$\frac{x^3+x^2-x-3}{x^2-3}$
Soluzione passo-passo
1
Dividere $x^3+x^2-x-3$ per $x^2-3$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-3;}{\phantom{;}x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-3\overline{\smash{)}\phantom{;}x^{3}+x^{2}-x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-3;}\underline{-x^{3}\phantom{-;x^n}+3x\phantom{;}\phantom{-;x^n}}\\\phantom{-x^{3}+3x\phantom{;};}\phantom{;}x^{2}+2x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3-;x^n;}\underline{-x^{2}\phantom{-;x^n}+3\phantom{;}\phantom{;}}\\\phantom{;-x^{2}+3\phantom{;}\phantom{;}-;x^n;}\phantom{;}2x\phantom{;}\phantom{-;x^n}\\\end{array}$
$x+1+\frac{2x}{x^2-3}$
Risposta finale al problema
$x+1+\frac{2x}{x^2-3}$