Esercizio
$\frac{x^3-4x-10}{x^2-x+6}$
Soluzione passo-passo
1
Dividere $x^3-4x-10$ per $x^2-x+6$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-x\phantom{;}+6;}{\phantom{;}x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-x\phantom{;}+6\overline{\smash{)}\phantom{;}x^{3}\phantom{-;x^n}-4x\phantom{;}-10\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-x\phantom{;}+6;}\underline{-x^{3}+x^{2}-6x\phantom{;}\phantom{-;x^n}}\\\phantom{-x^{3}+x^{2}-6x\phantom{;};}\phantom{;}x^{2}-10x\phantom{;}-10\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-x\phantom{;}+6-;x^n;}\underline{-x^{2}+x\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{;-x^{2}+x\phantom{;}-6\phantom{;}\phantom{;}-;x^n;}-9x\phantom{;}-16\phantom{;}\phantom{;}\\\end{array}$
$x+1+\frac{-9x-16}{x^2-x+6}$
Risposta finale al problema
$x+1+\frac{-9x-16}{x^2-x+6}$