Esercizio
$\frac{x^3-6x-10}{x+3}$
Soluzione passo-passo
1
Dividere $x^3-6x-10$ per $x+3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+3;}{\phantom{;}x^{2}-3x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+3\overline{\smash{)}\phantom{;}x^{3}\phantom{-;x^n}-6x\phantom{;}-10\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+3;}\underline{-x^{3}-3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{3}-3x^{2};}-3x^{2}-6x\phantom{;}-10\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n;}\underline{\phantom{;}3x^{2}+9x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{2}+9x\phantom{;}-;x^n;}\phantom{;}3x\phantom{;}-10\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n;}\underline{-3x\phantom{;}-9\phantom{;}\phantom{;}}\\\phantom{;;-3x\phantom{;}-9\phantom{;}\phantom{;}-;x^n-;x^n;}-19\phantom{;}\phantom{;}\\\end{array}$
$x^{2}-3x+3+\frac{-19}{x+3}$
Risposta finale al problema
$x^{2}-3x+3+\frac{-19}{x+3}$