Esercizio
$\frac{x^4-x^3-8x^2-2}{x^2-3x-1}$
Soluzione passo-passo
1
Dividere $x^4-x^3-8x^2-2$ per $x^2-3x-1$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-3x\phantom{;}-1;}{\phantom{;}x^{2}+2x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-3x\phantom{;}-1\overline{\smash{)}\phantom{;}x^{4}-x^{3}-8x^{2}\phantom{-;x^n}-2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-3x\phantom{;}-1;}\underline{-x^{4}+3x^{3}+x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}+3x^{3}+x^{2};}\phantom{;}2x^{3}-7x^{2}\phantom{-;x^n}-2\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3x\phantom{;}-1-;x^n;}\underline{-2x^{3}+6x^{2}+2x\phantom{;}\phantom{-;x^n}}\\\phantom{;-2x^{3}+6x^{2}+2x\phantom{;}-;x^n;}-x^{2}+2x\phantom{;}-2\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3x\phantom{;}-1-;x^n-;x^n;}\underline{\phantom{;}x^{2}-3x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}x^{2}-3x\phantom{;}-1\phantom{;}\phantom{;}-;x^n-;x^n;}-x\phantom{;}-3\phantom{;}\phantom{;}\\\end{array}$
$x^{2}+2x-1+\frac{-x-3}{x^2-3x-1}$
Risposta finale al problema
$x^{2}+2x-1+\frac{-x-3}{x^2-3x-1}$