Applicare la formula: $x^a=b$$\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}$, dove $a=15$, $b=-\frac{455}{27}$, $x^a=b=\left(\frac{1}{a}-y^2\right)^{15}=-\frac{455}{27}$, $x=\frac{1}{a}-y^2$ e $x^a=\left(\frac{1}{a}-y^2\right)^{15}$

Applicare la formula: $x+a=b$$\to x=b-a$, dove $a=-y^2$, $b=0$, $x+a=b=\frac{1}{a}-y^2=0$, $x=\frac{1}{a}$ e $x+a=\frac{1}{a}-y^2$

Applicare la formula: $\frac{a}{x}=b$$\to \frac{x}{a}=\frac{1}{b}$, dove $a=1$, $b=y^2$ e $x=a$