Esercizio
$\left(-3x^{3}+4x^{2}+6x-7\right):\left(x^{2}-2x-1\right)$
Soluzione passo-passo
1
Dividere $-3x^3+4x^2+6x-7$ per $x^2-2x-1$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-2x\phantom{;}-1;}{-3x\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-2x\phantom{;}-1\overline{\smash{)}-3x^{3}+4x^{2}+6x\phantom{;}-7\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-2x\phantom{;}-1;}\underline{\phantom{;}3x^{3}-6x^{2}-3x\phantom{;}\phantom{-;x^n}}\\\phantom{\phantom{;}3x^{3}-6x^{2}-3x\phantom{;};}-2x^{2}+3x\phantom{;}-7\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-2x\phantom{;}-1-;x^n;}\underline{\phantom{;}2x^{2}-4x\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}2x^{2}-4x\phantom{;}-2\phantom{;}\phantom{;}-;x^n;}-x\phantom{;}-9\phantom{;}\phantom{;}\\\end{array}$
$-3x-2+\frac{-x-9}{x^2-2x-1}$
Risposta finale al problema
$-3x-2+\frac{-x-9}{x^2-2x-1}$