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Divide all the terms of the differential equation by $x^2+1$
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$\frac{x^2+1}{x^2+1}\frac{dy}{dx}+\frac{3xy}{x^2+1}=\frac{6x}{x^2+1}$
Learn how to solve problems step by step online. (x^2+1)dy/dx+3xy=6x. Divide all the terms of the differential equation by x^2+1. Simplifying. We can identify that the differential equation has the form: \frac{dy}{dx} + P(x)\cdot y(x) = Q(x), so we can classify it as a linear first order differential equation, where P(x)=\frac{3x}{x^2+1} and Q(x)=\frac{6x}{x^2+1}. In order to solve the differential equation, the first step is to find the integrating factor \mu(x). To find \mu(x), we first need to calculate \int P(x)dx.