Impara online a risolvere i problemi di passo dopo passo. (x)->(-infinito)lim((9+2x^3)/(x-(x^6+x^2)^(1/2))). Applicare la formula: \lim_{x\to c}\left(\frac{a}{b}\right)=\lim_{x\to c}\left(\frac{\frac{a}{sign\left(c\right)fgrow\left(b\right)}}{\frac{b}{sign\left(c\right)fgrow\left(b\right)}}\right), dove a=9+2x^3, b=x-\sqrt{x^6+x^2}, c=- \infty , a/b=\frac{9+2x^3}{x-\sqrt{x^6+x^2}} e x->c=x\to{- \infty }. Applicare la formula: \lim_{x\to c}\left(\frac{a}{b}\right)=\lim_{x\to c}\left(\frac{radicalfrac\left(a\right)}{radicalfrac\left(b\right)}\right), dove a=\frac{9+2x^3}{-\sqrt{x^6+x^2}}, b=\frac{x-\sqrt{x^6+x^2}}{-\sqrt{x^6+x^2}} e c=- \infty . Applicare la formula: \lim_{x\to c}\left(\frac{a}{b}\right)=\lim_{x\to c}\left(\frac{splitfrac\left(a\right)}{splitfrac\left(b\right)}\right), dove a=\frac{9+2x^3}{-\sqrt{x^6+x^2}}, b=\frac{x-\sqrt{x^6+x^2}}{-\sqrt{x^6+x^2}} e c=- \infty . Applicare la formula: \frac{a}{a}=1, dove a/a=\frac{1}{2}.

(x)->(-infinito)lim((9+2x^3)/(x-(x^6+x^2)^(1/2)))