Esercizio
$-4x^3+x^2-4\:entre\:x-1$
Soluzione passo-passo
1
Dividere $-4x^3+x^2-4$ per $x-1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-1;}{-4x^{2}-3x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-1\overline{\smash{)}-4x^{3}+x^{2}\phantom{-;x^n}-4\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-1;}\underline{\phantom{;}4x^{3}-4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}4x^{3}-4x^{2};}-3x^{2}\phantom{-;x^n}-4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n;}\underline{\phantom{;}3x^{2}-3x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{2}-3x\phantom{;}-;x^n;}-3x\phantom{;}-4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n;}\underline{\phantom{;}3x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}3x\phantom{;}-3\phantom{;}\phantom{;}-;x^n-;x^n;}-7\phantom{;}\phantom{;}\\\end{array}$
$-4x^{2}-3x-3+\frac{-7}{x-1}$
Risposta finale al problema
$-4x^{2}-3x-3+\frac{-7}{x-1}$