Impara online a risolvere i problemi di passo dopo passo. ln(abs(arccot(x)))-ln(abs(arctan(x)))=2ln(abs(arccot(x))). Applicare la formula: a\ln\left(x\right)=\ln\left(x^a\right), dove a=2 e x=\left|\mathrm{arccot}\left(x\right)\right|. Applicare la formula: \ln\left(a\right)-\ln\left(b\right)=\ln\left(\frac{a}{b}\right), dove a=\left|\mathrm{arccot}\left(x\right)\right| e b=\left|\arctan\left(x\right)\right|. Applicare la formula: \ln\left(x\right)=\ln\left(y\right)\to x=y, dove x=\frac{\left|\mathrm{arccot}\left(x\right)\right|}{\left|\arctan\left(x\right)\right|} e y=\left|\mathrm{arccot}\left(x\right)\right|^2. Applicare la formula: \frac{a}{b}=c\to a=cb, dove a=\left|\mathrm{arccot}\left(x\right)\right|, b=\left|\arctan\left(x\right)\right| e c=\left|\mathrm{arccot}\left(x\right)\right|^2.

ln(abs(arccot(x)))-ln(abs(arctan(x)))=2ln(abs(arccot(x)))