Solve the equation with radicals $\sqrt[3]{5x+4}=4$

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Final answer to the problem

$x=12$
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Apply the formula: $x^a=b$$\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}$, where $a=\frac{1}{3}$, $b=4$, $x^a=b=\sqrt[3]{5x+4}=4$, $x=5x+4$ and $x^a=\sqrt[3]{5x+4}$

$5x+4=64$

Impara online a risolvere i problemi di equazioni con radici cubiche passo dopo passo.

$5x+4=64$

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Impara online a risolvere i problemi di equazioni con radici cubiche passo dopo passo. Solve the equation with radicals (5x+4)^(1/3)=4. Apply the formula: x^a=b\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}, where a=\frac{1}{3}, b=4, x^a=b=\sqrt[3]{5x+4}=4, x=5x+4 and x^a=\sqrt[3]{5x+4}. Apply the formula: x+a=b\to x=b-a, where a=4, b=64, x+a=b=5x+4=64, x=5x and x+a=5x+4. Apply the formula: a+b=a+b, where a=64, b=-4 and a+b=64-4. Apply the formula: ax=b\to \frac{ax}{a}=\frac{b}{a}, where a=5 and b=60.

Final answer to the problem

$x=12$

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Function Plot

Plotting: $\sqrt[3]{5x+4}-4$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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