Solve the equation with radicals $\sqrt[3]{x}=6$

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Solving: $\sqrt[3]{x}=6$
Solve instead: $\sqrt[3]{x=6}$

Final answer to the problem

$x=216$
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Step-by-step Solution

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1

Apply the formula: $x^a=b$$\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}$, where $a=\frac{1}{3}$, $b=6$, $x^a=b=\sqrt[3]{x}=6$ and $x^a=\sqrt[3]{x}$

$\left(\sqrt[3]{x}\right)^3=6^3$

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$\left(\sqrt[3]{x}\right)^3=6^3$

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Learn how to solve equazioni con radici cubiche problems step by step online. Solve the equation with radicals x^(1/3)=6. Apply the formula: x^a=b\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}, where a=\frac{1}{3}, b=6, x^a=b=\sqrt[3]{x}=6 and x^a=\sqrt[3]{x}. Apply the formula: \left(x^a\right)^b=x, where a=\frac{1}{3}, b=3, x^a^b=\left(\sqrt[3]{x}\right)^3 and x^a=\sqrt[3]{x}. Apply the formula: a^b=a^b, where a=6, b=3 and a^b=6^3.

Final answer to the problem

$x=216$

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Function Plot

Plotting: $\sqrt[3]{x}-6$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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