Final answer to the problem
$x=\frac{-4+\sqrt{20}}{2},\:x=\frac{-4-\sqrt{20}}{2}$
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Apply the formula: $x^2+bx+c=0$$\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}$, where $b=4$, $c=-1$, $bx=4x$, $x^2+bx=x^2+4x-1$ and $x^2+bx=0=x^2+4x-1=0$
$x=\frac{-4\pm \sqrt{4^2-4\cdot -1}}{2}$
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$x=\frac{-4\pm \sqrt{4^2-4\cdot -1}}{2}$
Learn how to solve problems step by step online. Solve the quadratic equation x^2+4x+-1=0. Apply the formula: x^2+bx+c=0\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}, where b=4, c=-1, bx=4x, x^2+bx=x^2+4x-1 and x^2+bx=0=x^2+4x-1=0. Apply the formula: a=b\to a=b, where a=x and b=\frac{-4\pm \sqrt{4^2-4\cdot -1}}{2}. Apply the formula: x=\frac{b\pm c}{f}\to x=\frac{b+c}{f},\:x=\frac{b-c}{f}, where b=-4, c=\sqrt{20} and f=2. Combining all solutions, the 2 solutions of the equation are.
Final answer to the problem
$x=\frac{-4+\sqrt{20}}{2},\:x=\frac{-4-\sqrt{20}}{2}$
