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1
Rewrite the expression $\sqrt{5+4x-x^2}$ inside the integral in factored form
$\int_{4}^{4}\sqrt{-\left(x-2\right)^2+9}dx$
2
Apply the formula: $\left[x\right]_{a}^{a}$$=0+C$, where $a=4$ and $x=\int\sqrt{-\left(x-2\right)^2+9}dx$
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