Final answer to the problem
$x=6$
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Express the numbers in the equation as logarithms of base $9$
$\log_{9}\left(x-5\right)+\log_{9}\left(x+3\right)=\log_{9}\left(9^{1}\right)$
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$\log_{9}\left(x-5\right)+\log_{9}\left(x+3\right)=\log_{9}\left(9^{1}\right)$
Learn how to solve problems step by step online. log9(x+-5)+log9(x+3)=1. Express the numbers in the equation as logarithms of base 9. Apply the formula: x^1=x, where x=9. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=9, x=x-5 and y=x+3. Apply the formula: \log_{a}\left(x\right)=\log_{a}\left(y\right)\to x=y, where a=9, x=\left(x-5\right)\left(x+3\right) and y=9.
Final answer to the problem
$x=6$
