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Apply the formula: $x^a=b$$\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}$, where $a=\frac{1}{3}$, $b=2$, $x^a=b=\sqrt[3]{2x-1}=2$, $x=2x-1$ and $x^a=\sqrt[3]{2x-1}$
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$2x-1=8$
Learn how to solve equazioni con radici cubiche problems step by step online. Solve the equation with radicals (2x-1)^(1/3)=2. Apply the formula: x^a=b\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}, where a=\frac{1}{3}, b=2, x^a=b=\sqrt[3]{2x-1}=2, x=2x-1 and x^a=\sqrt[3]{2x-1}. Apply the formula: x+a=b\to x=b-a, where a=-1, b=8, x+a=b=2x-1=8, x=2x and x+a=2x-1. Apply the formula: a+b=a+b, where a=8, b=1 and a+b=8+1. Apply the formula: ax=b\to \frac{ax}{a}=\frac{b}{a}, where a=2 and b=9.
