$x^2+12x+6$

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Final answer to the problem

$\left(x+6\right)^2-30$
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Step-by-step Solution

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Apply the formula: $x^2+bx+c$$=x^2+bx+c+\left(\frac{b}{2}\right)^2-\left(\frac{b}{2}\right)^2$, where $b=12$ and $c=6$

$x^2+12x+6+\left(\frac{12}{2}\right)^2- \left(\frac{12}{2}\right)^2$

Learn how to solve fattorizzazione polinomiale problems step by step online.

$x^2+12x+6+\left(\frac{12}{2}\right)^2- \left(\frac{12}{2}\right)^2$

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Learn how to solve fattorizzazione polinomiale problems step by step online. x^2+12x+6. Apply the formula: x^2+bx+c=x^2+bx+c+\left(\frac{b}{2}\right)^2-\left(\frac{b}{2}\right)^2, where b=12 and c=6. Apply the formula: \frac{a}{b}=\frac{a}{b}, where a=12, b=2 and a/b=\frac{12}{2}. Apply the formula: \frac{a}{b}=\frac{a}{b}, where a=12, b=2 and a/b=\frac{12}{2}. Apply the formula: a^b=a^b, where a=6, b=2 and a^b=6^2.

Final answer to the problem

$\left(x+6\right)^2-30$

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Plotting: $\left(x+6\right)^2-30$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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