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$\frac{dy}{dx}+\frac{3}{x}y=\frac{1}{x^2}$

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Solution

Formulas

Videos

Integrali di base

$\int xdx=\frac{1}{2}x^2+C$

Function Plot

Plotting: $\frac{dy}{dx}+\frac{3}{x}y+\frac{-1}{x^2}$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\left(x^2+1\right)\frac{dy}{dx}+3xy=6x$

$\left(x+\frac{y}{x}\right)dx-dy=0$

$x\frac{dy}{dx}+2y=3$

$\frac{dy}{dx}=\frac{x^3-2y}{x}$

$x^3\frac{dy}{dx}+3x^2y=x$

$x\frac{dy}{dx}+2y=x^{-3}$

$dy=\left(x-3y\right)dx$

Main Topic: Equazioni differenziali

Used Formulas

See formulas (1)

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