$\log_{8}\left(x\right)=\frac{1}{3}$

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Final answer to the problem

$x=2$
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Step-by-step Solution

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Apply the formula: $\log_{a}\left(x\right)$$=\frac{\log \left(x\right)}{\log \left(a\right)}$, where $a=8$

$\frac{\log \left(x\right)}{\log \left(8\right)}=\frac{1}{3}$

Learn how to solve equazioni logaritmiche problems step by step online.

$\frac{\log \left(x\right)}{\log \left(8\right)}=\frac{1}{3}$

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Learn how to solve equazioni logaritmiche problems step by step online. log8(x)=1/3. Apply the formula: \log_{a}\left(x\right)=\frac{\log \left(x\right)}{\log \left(a\right)}, where a=8. Apply the formula: \frac{a}{b}=\frac{c}{f}\to af=bc, where a=\log \left(x\right), b=\log \left(8\right), c=1 and f=3. Apply the formula: a\log_{b}\left(x\right)=\log_{b}\left(x^a\right), where a=3 and b=10. Apply the formula: \log_{a}\left(x\right)=\log_{a}\left(y\right)\to x=y, where a=10, x=x^3 and y=8.

Final answer to the problem

$x=2$

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Function Plot

Plotting: $\log_{8}\left(x\right)-\frac{1}{3}$

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6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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